Question

A tower stands on the ground. from a point on the ground which is 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 30. find the height of the tower

Answer 1

I think it is right and hope it help you

Answer 2

Step-by-step explanation:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/20

30/√3 = AB

AB = 20/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 20/√3 × √3/√3

AB = 20√3/3

Therefore, the height of the tower is 20√3/3