Question

a tower stands verically on the ground. from a point on the ground 100 m away from the foot of tower the angle of elivation from the the top of tower is 45°. find the height of tower​

Answer 1

Answer:

height of the tower = 100m

Answer 2

ANSWER

REF.Image.

30m away / 45∘ inclination.

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m 

CB=30m

Angle of elevation =45∘

∠ACB=45∘

Since tower is vertical to ground

∠ABC=90∘

Now tanC=sideadjacenttoangleCsideopptoangleC

tanC=CBAB

tan45=CBAB

1=30H

H=30

Hence height of tower = 30m