Question

A tower stands vertically on abank of a canal . From a point on the other bank directly opposite to the tower , the angle of elevation of the top of the tower is 60° . from another point 10 m away from this point on the line joining this point to the foot of the tower the angle of elevation of the top of the tower is 45°. find the height of the tower​

Answer 1

Answer:

AB = H cm

ACB=60°

ADB= 45°

AB/BC= Tan 60°

H/10-h=

$\sqrt{2}$

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