a tower stands vertically on the ground from a point 15 metres away from the foot of the tower the angle of elevation of the top of the tower is 45 degrees what is the height of the tower
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Step-by-step explanation:
Refer the attachment......
The ans is 15 itself...u have to take tan 45° = 1
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Answer:
Let AB be a tower with height hm, BC be the ground level
Given, Angle of Elevation = 45°
Ground level (BC) = 15m
In ∆ABC, h/15 = tan45°
h/15 = 1/1
h = 15m
Hence, height of the tower is 15m
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