Question

A tower stands vertically on the ground. From
a point on the ground which is 25 m away from
the foot of the tower, the angle of elevation of
the top of the tower is found to be 459 Then
find the height (in meters) of the tower.​

Answer 1

30m away / 45  

∘

 inclination.

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m  

CB=30m

Angle of elevation =45  

∘

 

∠ACB=45  

∘

 

Since tower is vertical to ground

∠ABC=90  

∘

 

Now tanC=  

sideadjacenttoangleC

sideopptoangleC

​  

 

tanC=  

CB

AB

​  

 

tan45=  

CB

AB

​  

 

1=  

30

H

​  

 

H=30

Hence height of tower = 30m

Answer = option C=30m