Question

A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in metres) of the tower is:​

Answer 1

Answer:

yep

Step-by-step explanation:

30m away / 45  

∘

 inclination.

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m  

CB=30m

Angle of elevation =45  

∘

 

∠ACB=45  

∘

 

Since tower is vertical to ground

∠ABC=90  

 

Now tan C=  side adjacent to angle C

side opp to angle C

​  

 

tanC=  CB *AB

​  

 

tan45=  CB* AB

​  

 

1=  

30

H

​  

 

H=30

Hence height of tower = 30m

Answer = 30m

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