Question

A tower stands vertically on the ground.From a point on the ground which is 25m away from the foot of the tower,the angle of elevation of the top of the tower is found to be 45degree.Then the height (in metres) of the tower is: *​

Answer 1

Answer:-

Given:-

• 25 m away from foot of the tower
• The angle of elevation of the top of the tower is found to be 45°

To find:-

• The height (in meters) of the tower

Solution:-

Let the height of the tower be ' h ' meters

Now,

In ΔACB

$⇒tan 45^{2} = \frac{AB}{BC} = \frac{h}{25}$

$⇒l = \frac{h}{25}$

$⇒\boxed{h=25m}$

Therefore, the height of the tower is " 25 m "