A tower stands vertically on the ground. from a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 60 ∘ . what is the height of the tower?
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Use tan60=AB/BC For a triangle Abc, where B =90
let ab = height and bc= distance from perpendicular
Thus,
√3= ab/20
So, ab =20√3
let ab = height and bc= distance from perpendicular
Thus,
√3= ab/20
So, ab =20√3
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