A tower stands vertically on the ground. From a point on the ground which is 25 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45°. Then the height (in meters) of the tower is
A. 25√2
B. 25√3
C. 25
D. 12.5
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Answer:
Step-by-step explanation:
Consider a right angled triangle ABC,right angle is at B .From question , BC=25m and angle at C=45 degrees
Height of the tower =AB
Tan45=AB÷BC= 1
AB=BC =25m
Height of the tower =AB=25m
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