a tower stands vertically on the ground from a point on the ground which is 21 m away from the foot of the tower the angle of elevation of the top of the tower is found to be 30 degree find the height of the tower
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rohinipatil1978:
See below explanation
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Answer:
Step-by-step explanation:
Given :
Height of tower : h = AB
Distance between point : 21 m =BC
¢= 30'
Solution:
Tan ¢ = AB/BC
Tan 30' = h/21
1/√3= h/21
h = 21/√3
=21/√3 × √3/√3 ----rationalizing denom.
=21√3 /3
=7√3 m
Hence, height of tower is 7√3 m.
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