Question

A tower stands vertically on the ground. From
a point on the ground which is 15 metres alway
from the foot of the tower, the angle of elevation
of the top of the tower is 60°. The height of the
tower is??​

Answer 1

Step-by-step explanation:

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Answer 2

Here's the Solution :

Let AB be the tower

and C be the point on ground which is 15m away . (refers to attached figure )

Given the angle formed by tower is 60°

Therefore ,

tan60° = AB/BC

=>√3 = AB/BC

=> √3BC = AB

=> AB = √3 ×15m ( BC = 15m)

=> AB = 15√3m

Therefore, height of tower is 15√3m