Question

A tower stands vertically on the ground. From a point which is 15 meter away from the
foot of the tower, the angle of elevation of the top of the tower is 45°. What is the height
of the tower?
​

Answer 1

Let the height of the tower = h m

Distance of the point of observation from the foot of the tower =15m

Angle of elevation of the top of the tower =45

∘

From the figure

tanθ=

adjacentsidetotheangleθ

oppositesidetotheangleθ

tan45

∘

=

15

h

⇒1=

15

h

⇒h=15×1=15

∴ The height of the tower =15m

Answered By=shreyash. .........

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