Question

a tower stands vertically on the ground from a point which is 15m away from the foot of the tower. the angle of elevation of the top of the tower is 45°. what is the height of tower​

Answer 1

Answer:

Step-by-step explanation:

Let the height of the tower = h m

Distance of the point of observation from the foot of the tower =15m

Angle of elevation of the top of the tower =45  

∘

 

From the figure

tanθ=  

adjacentsidetotheangleθ

oppositesidetotheangleθ

​  

 

tan45  

∘

=  

15

h

​  

⇒1=  

15

h

​  

⇒h=15×1=15

∴ The height of the tower =15m