A tower stands vertically on the ground. From a point which is 15 meter away from the
foot of the tower, the angle of elevation of the top of the tower is 45°. What is the height
of the tower?
d the broken part bends so that the top of the tree touche
Answers
Answered by
0
Answer:
the tower is 15 metrers long
Answered by
1
Answer:
15 cm
Step-by-step explanation:
let the height of the tower be h cm.
so,
AB = h m
CB = 15 m
∆ ACB = 45°
so ,
tan 45° = AB/CB
1 = h / 15
15 m = h.
hope this is helpful for you...
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