Math, asked by nandinimarla2006, 3 months ago

A tower stands vertically on the ground. From a point which is 15 meter away from the
foot of the tower, the angle of elevation of the top of the tower is 45°. What is the height
of the tower?
d the broken part bends so that the top of the tree touche​

Answers

Answered by hitesh1619
0

Answer:

the tower is 15 metrers long

Answered by ritusingh1128
1

Answer:

15 cm

Step-by-step explanation:

let the height of the tower be h cm.

so,

AB = h m

CB = 15 m

∆ ACB = 45°

so ,

tan 45° = AB/CB

1 = h / 15

15 m = h.

hope this is helpful for you...

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