A tower stands vertically on the ground. From a point which is 15 meter away from the foot of the tower, the angle of elevation of the top of the tower is 45°. What is he height of the tower?
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Answer:
h=15mtrs
Step-by-step explanation:
theta=angle of elevation=45°
In triangle ABC
Tan theta =opposite side / adjacent side
Tan45°= height/distance
1=h/15
h=15 mtrs
Therefore, height of the tower=15mtrs
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