A tower stands vertically on the ground. from a point which is 15 meters away from the foot of tower, the angle of elevation of the top of the tower is 45 degrees. what is the height of the tower.
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Answered by
11
tan 45= perpendicular / base
so 1 = height of the tower/ distance from its foot
so, 1 = H/15
so, H = 15 m
so 1 = height of the tower/ distance from its foot
so, 1 = H/15
so, H = 15 m
Answered by
6
⚡⚡hey buddyyyyy here is ur answer➖➖
⏩ given : distance from foot of tower= adjacent side = 15m
⏹ height of tower be opposite side
⏩ tan tita = 45
then we have , tan tita = opposite ÷ adjacent
tan 45= opp÷ adj
1 = opposite÷ 15
0pposite side = height of tower = 15× 1 = 15m
⏩ given : distance from foot of tower= adjacent side = 15m
⏹ height of tower be opposite side
⏩ tan tita = 45
then we have , tan tita = opposite ÷ adjacent
tan 45= opp÷ adj
1 = opposite÷ 15
0pposite side = height of tower = 15× 1 = 15m
asadlion2017:
yes bro
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