Question

A tower stands vertically on the ground from a point with his 12 metres away from the foot of the tower the angle of elevation of the top of the tower is 45 degrees. what is the height of the tower

Answer 1

Step-by-step explanation:

Given that,

Distance foot of tower from him = 12 m

angle of elevation of top of the tower from him = 45°

here,

height of tower be h

tan45° = h/12 1

h = 12 m

so,

The height of tower = 12 m

Answer 2

The height of the tower is :

• Given : Distance between point and tower = 12 m, angle of elevation of the top of the top of the tower = 45°

•In right angled ∆PQR,

Angle PQR = 90°

tan 45° = QR / PQ = h / 12 m

• tan 45 ° = 1

°•° 1 = h / 12m

• h = 12 m

• Therefore, the height of the tower is 12 m