A tower subtends an angle at a point A in the plane of its base and the angle of depression of
the foot of the tower at a point b metres just above A is . Prove that the height of tower is b
tan cot .
Answers
Answered by
1
Answer:
CD=btanαcotβ [ Hence proved ]
Step-by-step explanation:
Here, CD is the height of the tower.
In △ABC,tanβ=
AC
AB
⇒ tanβ=
AC
b
∴ AC=
tanβ
b
∴ AC=bcotβ ------ ( 1 )
In △ACD,tanα=
AC
CD
⇒ CD=tanα×AC
⇒ CD=tanα×bcotβ [ From ( 1 ) ]
∴ CD=btanαcotβ [ Hence proved ]
HOPE THIS HELPS OUT TO U
PLS MARK ME AS BRAINLIST
Similar questions
Social Sciences,
1 month ago
Math,
1 month ago
Math,
1 month ago
Computer Science,
2 months ago
Math,
8 months ago
Math,
8 months ago
Chemistry,
8 months ago