Question

a town has a population 10000 it increases @ 10% per year what will be its population after 2 years and what was its population 2 years back​

Answer 1

Increase= 10000*+(2*(10%10000))
= 10000*+(2*1000)
=10000+2000
=12000

Two years ago=10000*-(2*(10%10000))
= 10000*-(2*1000)
=10000-2000
=8000

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Answer 2

population ( this year ) = 10000

increase per year = 10%

increase per year ( in no. ) = 10%of 10000

= 10/100×10,000

= 1000

population after 2 year = 10,000+(1000×2 )

= 10,000+ 2000

= 12,000

hence , population after 2 year is 12,000

population before 2 year = 10,000 - (1,000×2)

= 10,000 - 2,000

= 8,000

hence , population before 2 year is 8,000

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