Chemistry, asked by devesh0804, 1 year ago

A toy balloon originally held 1.0 gm of He gas and had a radius 10 cm. During the night
the gas effused from the balloon. Assuming ideal gas behavior, under these constant
conditions, what was the radius of the balloon the next morning?​

Answers

Answered by Anonymous
7

Answer:

Balloon is a sphere whose volume is 4/3* r3

1gm He gas occupies the volume = 4/3* 10*10*10

So, 0.75gm gas( left after diffusion) will occupy the volume

= 4/3* 10*10*10* 0.75

The volume of balloon after diffusion:

4/3* r3 = 4/3 *10*10*10*0.75

r3 = 750

r = 9.08cm

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