Question

a toy bus of mass 5kg is moving with a veloci ty 2m/s a constant force of 5n acts on the objects what will be the velocity after 3 s

Answer 1

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Answer 2

Concept:

We need to utilize the concept of kinematic equations of motion. The first kinematic equation of motion is expressed as- v = u + at.

Given:

Mass of toy bus, m = 5 kg

Initial velocity of toy bus, u = 2m/s

Force = 5N

Find:

We need to determine the velocity of the toy bus after 3 s, v =?

Solution:

We know, Force is represented by the equation, F = ma where m is the mass and a is the acceleration produced by the body

We have, force, F as 5 N and mass of toy bus, m as 5 kg

Therefore, the equation of force, F = ma becomes-

5 = 5a

Therefore, a = 5/5

a = 1m/s²

From the first kinematic equation of motion

v = u + at

We have initial velocity, u as 2m/s

Therefore, the equation becomes-

v = 2 + (1)(3)

v = 2 + 3

v = 5m/s

Thus, the velocity of the toy bus after 3 seconds is 5m/s.

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