Question

A toy car accelerates 3m/s to 5m/s in 5sec. What is its acceleration?

Answer 1

Provided that:

• Initial velocity = 3 mps
• Final velocity = 5 mps
• Time = 5 seconds

To calculate:

• The acceleration

Solution:

• The acceleration = 0.4 mps sq.

Using concept(s):

• To solve this question we can use either first equation of motion or acceleration formula.

Using formula(s):

• Acceleration formula:

• a = (v-u)/t

• First equation of motion:

• v = u + at

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Required solution:

By using first equation of motion.

→ v = u + at

→ 5 = 3 + a(5)

→ 5 - 3 = 5a

→ 2 = 5a

→ 2/5 = a

→ a = 2/5 mps sq.

→ Acceleration = 0.4 mps sq.

By using acceleration formula:

→ a = (v-u)/t

→ a = (5-3)/5

→ a = 2/5

→ Acceleration = 0.4 mps sq.

Answer 2

Question :-

• A toy car accelerates 3 m/s to 5 m/s in 5 seconds . Calculate its Acceleration .

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Answer :-

• Acceleration of car = 0.4 m/s² .

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Explanation :-

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∓ Here, it is given that, A car accelerates from 3 m/s to 5 m/s in 5 seconds . And, we have to calculate the Acceleration .

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• Now, let's solve step by step -----

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◆ Formula Required :-

• $\sf{ A= \frac{v - u}{t} }$

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◆ Here ,

• A denotes to Acceleration
• V denotes to Final Velocity
• U denotes to Initial Velocity
• T denotes to Time

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∴ By substituting the given values :-

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$\dashrightarrow \: \sf{Acceleration = \frac{5 - 3}{5} } \\ \\ \dashrightarrow \: \sf{Acceleration = \frac{2}{5} } \\ \\ \dashrightarrow \: \sf{Acceleration =0.4 }$

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Hence :-

• Acceleration of car = 0.4 m/s² .

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