Question

A toy car falls to the ground in 0.4sec calculate it's speed just before striking ground (g = 10 m/s)

Answer 1

t=0.4 sec, g=10m/s, u=0, v=?
v= u + at
v= 0 + 10*0.4
v= 4m/s.
Hence, speed of toy car falls is 4m/s.

Answer 2

The speed of the toy car just before striking the ground is approximately

5.66 m/s.

The speed of the toy car just before striking the ground can be calculated using the following formula:

v = √(2gh), where v is the speed, g is the acceleration due to gravity (10 m/$s^{2}$), h is the height fallen, and t is the time taken to fall.

First, find the height fallen:

h = 1/2g$t^{2}$, where t = 0.4 sec

h = 1/2 * 10 * $(0.4)^{2}$ = 1.6 m

Next, substitute the values of g and h into the formula:

v = √(2gh) = √(2 * 10 * 1.6) = √(32) = 4√2 m/s

It's important to note that this calculation assumes that the only force acting on the toy car is gravity, and does not take into account any air resistance or other factors that could affect its speed and trajectory.

For more such questions on speed: https://brainly.in/question/26886879

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