Question

A toy car is moving in positive direction from a speed of 19 m/s to 40 m/s
in 7 sec. What is the acceleration of the toy car?

Answer 1

Answer:

Acceleration=v -u/t

=[40-19]/7

=21/7

=3 meter per second square

Above:

V= final velocity

U=initial velocity

T= time taken

Step-by-step explanation:

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Answer 2

Answer

• Acceleration of the toy car , a = 3 m/s²

Given :

• A toy car is moving in positive direction from a speed of 19 m/s to 40 m/s  in 7 sec

To Find :

• The acceleration of the toy car

Formula Used :

• $\bf a=\dfrac{v-u}{t}$

Solution :

We know that , " Acceleration is defined as the rate of change of velocity "

Here ,

Initial velocity , u = 19 m/s

Final velocity , v = 40 m/s

Time , t = 7 s

⇒ Acceleration , a = ( v - u ) / t

⇒ a = ( 40 - 19 ) / 7

⇒ a = 21 / 7

⇒ a = 3 m/s²

More Info :

Equations of Motion :

• v = u + at
• s = ut + 1/2 at²
• v² - u² = 2as