Question

A toy car of mass 20 kg is moving at 10 m/s' and another toy truck of mass 10 kg is moving at 40
m/s' on a parallel track in the same direction. The acceleration of centre of mass of the two is
(A) 10 m/s2
(B) 20 m/s?
(C) 40 m/s?
(D) zero
​

Answer 1

Answer:

The both of the toys are traveling in

Y direction. So,

Y=m1*V1 + m2*V2

/m1 + m2

= 20*10 + 10*40/30

=200 + 400 / 30

=600 / 30 = 20ms^-2

So B) is the correct option

Answer 2

The acceleration of center of mass of the two is $20\ m/s^2$.

Explanation:

It is given that,

Mass of the toy car, m = 20 kg

Speed of the toy car, v = 10 m/s

Mass of the truck, m' = 10 kg

Speed of the truck, v' = 40 m/s

Let a is the acceleration of center of mass of the two. It is given by :

$a=\dfrac{mv+m'v'}{m+m'}$

$a=\dfrac{20\times 10+10\times 40}{20+10}$

$a=20\ m/s^2$

So, the acceleration of center of mass of the two is $20\ m/s^2$. Hence, this is the required solution.

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