A toy car of mass m is having two similar rubber
Answers
vibrant period of toy car is 2π√(m/k)
A toy car of mass m is having two
similar rubber ribbons attached to it. The force constant of each rubber ribbon is k and surface is frictionless the car is displaced from mean position by xcm and released. At mean postion the ribbons are undeformed. Vibration period is
solution :- we know, time period , T = 2π√{inertial factor/spring factor}
inertial factor = m
when toy car is stretched along left side of ribbon, ribbon attached right side of car doesn't play any role in restoring force.
so, restoring force = kx and hence spring factor = k
the time period , T = 2π√(m/k)
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