Question

A toy car was moving with a speed of 20 cm/s. Its speed became 50 cm/s after traversing a distance of 1m. calculate the acceleration of the car?​

Answer 1

Answer

• Acceleration of the car , a = 0.105 m/s²

Given

• A toy car was moving with a speed of 20 cm/s. Its speed became 50 cm/s after traversing a distance of 1 m

To Find

• Acceleration of the car

Solution

Initial velocity , u = 20 cm/s = 0.2 m/s

Final velocity , v = 50 cm/s = 0.5 m/s

Distance , s = 1 m

Acceleration , a = ? m/s²

Use 3rd equation of motion .

⇒ v² - u² = 2as

⇒ 0.5² - 0.2² = 2a(1)

⇒ 0.25 - 0.04 = 2a

⇒ 0.21 = 2a

⇒ a = 0.105 m/s²

Answer 2

Answer:

We know that acceleration is the rate of change of velocity. Thus,

$a = \frac{v}{t}$

If the car moves 20 cms every second, i.e, 0.2 m every second, it needs 5 secs to move 1 m.

After it travelles 1 m, the velocity changes from 0.2 m every second to 0.5 m every second.

So, acceleration will be:

$a = \frac{v}{t}$

$a = \frac{v2 - v1}{t}$

$a = \frac{0.5 - 0.2}{5}$

$a = \frac{0.3}{5}$

$a = 0.06 \: {ms}^{ - 2}$

Hope this helps.

Thanks.