A toy car was moving with a speed of 20 cm/s. Its speed became 50 mis after traversing
distance of im. Calculate the acceleration of the car.
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Answer:
Acceleration of the car , a = 0.105 m/s²
Given
A toy car was moving with a speed of 20 cm/s. Its speed became 50 cm/s after traversing a distance of 1 m
To Find
Acceleration of the car
Solution
Initial velocity , u = 20 cm/s = 0.2 m/s
Final velocity , v = 50 cm/s = 0.5 m/s
Distance , s = 1 m
Acceleration , a = ? m/s²
Use 3rd equation of motion .
⇒ v² - u² = 2as
⇒ 0.5² - 0.2² = 2a(1)
⇒ 0.25 - 0.04 = 2a
⇒ 0.21 = 2a
⇒ a = 0.105 m/s²
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