Question

A toy car was moving with a speed of 20cm/s It's speed became 50m/s after travering a distance of 1m . Calculate the acceleration of the car

Answer 1

Given,

• Initial Speed (u) = 20 cm/s = 0.2 m /s
• Final Speed (v) = 50 m/s
• Displacement (s) = 1 m

According to the Newton's 3rd equation of motion,

$\boxed{\bold{v^2=u^2-2as}}$

Applying the values to the equation,

$\bold{(50)^2=(0.2)^2-2a(1)}$

$\bold{\implies{2500=0.04-2a}}$

$\bold{\implies{2500-0.04=-2a}}$

$\bold{\implies{2499.96=-2a}}$

$\bold{\implies{a=\frac{-2499.96}{2}}}$

$\boxed{\bold{\therefore{a=-1249.98m/s^2}}}$

Here,

Acceleration is negative.