A toy car was moving with a speed of 20cm/s lts speed became 50m/s after traversing a distance of 1m. calculate the acceleration of the car.
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Answer:
Correct option is
B
5ms
−2
Given,
a
t
=3m/s
2
v=20m/s
r=100m
Centripetal acceleration,
a
c
=
r
v
2
a
c
=
100
20×20
=4m/s
2
The resultant acceleration,
a=
(a
t
)
2
+(a
c
)
2
a=
(3)
2
+(4)
2
=
25
=5m/s
2
The correct option is B.
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