A toy duck is floating in a cylindrical tub 20cm diameter that is partially filled with water.Calculate the level of water rise in the cylinder when a silver crown weighing 100gm is put on the duck’s head,if the density of water is 1gm/cm^3 and density of silver is 10.49gm/cm^3?
Answers
Answered by
0
When the silver is placed in the toy duck it displaces a volume of water equal to its own volume.
Density = Mass /Volume
Volume = Mass / Denisty
volume of silver = 100 / 10.49 = 9.533 cm³
Volume of water displaced = 9.533 cm³
Volume = πr²h
9.533 = 3.142 × 10² × h
h = 9.533 / 314.2
h = 0.0303
Density = Mass /Volume
Volume = Mass / Denisty
volume of silver = 100 / 10.49 = 9.533 cm³
Volume of water displaced = 9.533 cm³
Volume = πr²h
9.533 = 3.142 × 10² × h
h = 9.533 / 314.2
h = 0.0303
Answered by
3
Answer:
Explanation:
When the silver is placed in the toy duck it displaces a volume of water equal to its own volume.
Density = Mass /Volume
Volume = Mass / Denisty
volume of silver = 100 / 10.49 = 9.533 cm³
Volume of water displaced = 9.533 cm³
Volume = πr²h
9.533 = 3.142 × 10² × h
h = 9.533 / 314.2
h = 0.0303
Similar questions