Question

a toy in the shape of a hemisphere surmounted by a right circular cone the height of the cone is 10 cm and the diameter of the base is 6 cm find the volume of the toy if a cube circumstances the toy then find difference between the volume of the cube and the toy also find the total surface area of the toy

Answer 1

Answer:

Radius of the hemisphere and the cone = 4 cm

Height of the cone = 4 cm

Volume of the toy = volume of the hemisphere + volume of the cone

A cube circumscribes the given solid. Therefore, edge of the cube should be 8 cm.

Volume of the cube = 83 = 512 cm3

Difference in the volumes of the cube and the toy = 512 - = 310.86 cm3

Total surface area of the toy = curved surface area of cone + curved surface area of hemisphere

= rl + 2r2, where l = == 4

= r (l + 2r)

= 4 (4 + 2 4)

=fraction numerator 88 cross times 4 left parenthesis square root of 2 plus 8 right parenthesis over denominator 7 end fraction

= 171.68 cm2