Question

A toy is created by placing a cylinder of height 5 cm on a cone of same perpendicular height . If the cylinder and cone both have the same inner diameter of 6 cm, then find the volume of the toy.​

Answer 1

h1=h2=5cm

R=3cm

v=v of cl+v of c

v=πr^2h+1/3πr^2h

v=πr^2(h+1/3h)

v=π3^2(5+5/3)

v=π9(20/3)

v=π60

v=22/7×60

v=22(8.57)

v=188.54

Answer 2

The volume of the toy is $188.4\ cm^3$ .

Given :

Height of cylinder and cone , h = 5 cm .

Diameter of cylinder and cone , d = 6 cm .

Therefore , radius is , r = 3 cm .

The volume of toy = volume of cylinder + volume of cone .

$V=\pi r^2h+\dfrac{\pi r^2 h}{3}\\\\V=\dfrac{4\pi r^2h}{3}$

Putting value of r and h in above equation , we get :

$V=\dfrac{4\times 3.14 \times 3^2\times 5}{3}\\\\V=188.4\ cm^3$

Hence , this is the required solution .

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