A toy is in the form of a cone mounted on a hemisphere .the diameter of the base and the height oA toy is in the form of a cone mounted on a hemisphere .the diameter of the base and the height of the cone are 6cm and 4cm find the surface areaf the cone are 6cm and 4cm find the surface area
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Answered by
2
CSA of cone = πrl
=(22/7)(7)(√(r²+h²))
=(22)(√7²+(31-7)²)
=(22)(√49+576)
=(22)(√625)
=(22)(25)
=550 cm²
CSA of hemisphere=2πr²
=2(22/7)(7²)
=(44/7)(49)
=(44)(7)
=308 cm²
Therefore, total surface area of the toy = CSA of cone + CSA of hemisphere
=550+308
=858 cm²
=(22/7)(7)(√(r²+h²))
=(22)(√7²+(31-7)²)
=(22)(√49+576)
=(22)(√625)
=(22)(25)
=550 cm²
CSA of hemisphere=2πr²
=2(22/7)(7²)
=(44/7)(49)
=(44)(7)
=308 cm²
Therefore, total surface area of the toy = CSA of cone + CSA of hemisphere
=550+308
=858 cm²
Answered by
4
HLO MATE HERE IS UR ANSWER
A toy in the form of cone mounted on a hemisphere
The diametere of the base = 6 cm
2r = 6
r = 6\ 2
r = 3 { Radius of the base }
and the height of the cone ( h) = 4 cm
WE KNOW THAT
lsquare = h square + r square
= 4 square + 3 square
16 +9
l square = 25
l = root 25
slant height of cone l = root 5
T S A of the toy = C S A of cone and C S A of hemisphere
pie rl + 2 pie r square
pie r ( l + 2 r )
3.14 × 3 ( 5 + {2× 3 } )
9.42 × [ 5+6 ]
9.42 × 11
103.62 cm square
HOPE THIS WILL HELPU
@ RUDEDOLL❤❤❤❤
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