A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius .the total height of the toy is 15 5 cm . find the total surgace area of the toy? only right answer can be put in answer key .
Answers
Answer:
rad. of cone=rad. of hemisphere =3.5cm(given)
Also,
ht of toy=15.5cm(given)
ht of hemisphere = 3.5cm
ht of cone = 15.5 - 3.5
=12cm
slant ht. of cone =under root h^2+r^2
=under root (12^2+3.5^2)
= under root 144+12.25
= under root 156.25
12.5cm
CSA of hemisphere = 2×22/7×(3.5)^2
=77cm^2
CSA of cone = 22/7×3.5×12.5
137.5cm^2
TSA of toy=CSA of hemisphere +CSA of cone
77+137.5
= 214.5cm^2
Given :
A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius . The total height of the toy is 15.5 cm .
To find :
Find the total surface area of the toy.
Solution :
Total surface area of toy = CSA of cone + SA of hemisphere
Total height of toy = 15.5 cm
Radius of cone = 3.5 cm
∴ Height of cone, h = (15.5 - 3.5) = 12 cm
∴ Slant height, l = √(h² + r²)
⇒ l = √{(12² + (3.5)²}
⇒ l = √{144 + 12.25}
⇒ l = √156.25
⇒ l = 12.5 cm
Now. csa of cone :
Now, surface area of hemisphere :
Therefore,