Question

A toy is in the form of a cone of radius 4cm and mounted on a cylinder of the same radius. the height of cylindrical part is 14 cm and the height of the conical part is 3cm. Find the total surface area of the toy​

Answer 1

Answer:

Height of the cylindrical part =13=13cm

Radius of cone , cylinder and hemi sphere=5=5cm

r=5cm for hemisphere cylinder and cone.

Height of cone h=h=30-5-13=1230−5−13=12

The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent

A=2\pi r^2+2\pi r H+\pi r(\sqrt{h^2+r^2})A=2πr

2

+2πrH+πr(

h

2

+r

2

)

A=2\pi \times 5\times 5+2\pi \times 5\times 13+\pi \times 5(\sqrt{5^2+12^2})A=2π×5×5+2π×5×13+π×5(

5

2

+12

2

)

A=770cm^2A=770cm

2

Answer 2

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