A toy is in the form of a cone of radius 4cm and mounted on a cylinder of the same radius. the height of cylindrical part is 14 cm and the height of the conical part is 3cm. Find the total surface area of the toy
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Answer:
Height of the cylindrical part =13=13cm
Radius of cone , cylinder and hemi sphere=5=5cm
r=5cm for hemisphere cylinder and cone.
Height of cone h=h=30-5-13=1230−5−13=12
The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent
A=2\pi r^2+2\pi r H+\pi r(\sqrt{h^2+r^2})A=2πr
2
+2πrH+πr(
h
2
+r
2
)
A=2\pi \times 5\times 5+2\pi \times 5\times 13+\pi \times 5(\sqrt{5^2+12^2})A=2π×5×5+2π×5×13+π×5(
5
2
+12
2
)
A=770cm^2A=770cm
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