Question

a toy is in the form of a right circular cylinder with a hemisphere on one end and a cone on the other the height and the radius of the cylindrical part are 13 cm and 5 cm respectively the radii of the hemispherical and the colonial part are the inner as that of the cylindrical part calculate the surface area of the toys if the height of the conical part is 12 cm

Answer 1

Total height= 30cm
height of cylinder=13cm
height of cone=30-18 (radius of hemisphere=height)
therefore height of cone= 12cm

C.S.A. of hemisphere:
2*22/7*5^2
=157.14 cm^2
C.S.A. of cylinder:
2*22/7*5*13
=408.571 cm^2
C.S.A of cone :
22/7*5*13
=204.28
Adding all C.S.As we get
  408.57
  204.28
+157.14
=769.99m^2 [Ans. =Surface area of toy]

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