a toy is in the form of cone if radius 3.5 CM mounted on a hemisphere of same radius. the total height of toy is 15.5cm . find the TSA of the toy
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Answered by
17
radius=3.5
height =15.5
TSA=πr(r+l)
22/7*3.5(3.5+15.5)
=209
height =15.5
TSA=πr(r+l)
22/7*3.5(3.5+15.5)
=209
jaat39:
your answer is wrong correct answer is 214
oh
I'm really sorry
Answered by
36
surface area of toy = c.s.a of cone + c.s.a of hemisphere
πrl + 2πr^
height of cone = 12cm., because the height of hemispher will be sub. =3.5
so, l = √ r^ + h^
√ 3.5^ + 12^
√ 156.25
12.5 cm
now, 2π r^ + π rl
π r ( 2 r + l )
22/ 7 * 3.5 ( 2* 3.5 + 12 )
11 ( 19)cm^
214 cm^
hope it will help u...!!! nd if mine answer helps u plzz mark as brain list
πrl + 2πr^
height of cone = 12cm., because the height of hemispher will be sub. =3.5
so, l = √ r^ + h^
√ 3.5^ + 12^
√ 156.25
12.5 cm
now, 2π r^ + π rl
π r ( 2 r + l )
22/ 7 * 3.5 ( 2* 3.5 + 12 )
11 ( 19)cm^
214 cm^
hope it will help u...!!! nd if mine answer helps u plzz mark as brain list
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