a toy
is in the form of cone mounted on a hemisphere with same radius the diameter of a base of the conical portion is 6 cm and its height is 4 cm the surface area of the toy is
Answers
Answer:
The toy is in form of a cone above a hemisphere
The surface area of the toy would be equal to
Curved surface area of cone + curved surface area of hemisphere
= πrl + 2πr²
height of cone = 4 cm
diameter of cone = 6cm
radius = 3 cm
slant height = √4² +3² =√25 = 5 cm
Total surface area of toy would be
π * 3* 5 + 2π * 3 * 3 = 33π cm² = 103.62 cm²
Volume of the toy would be equal to
volume of hemisphere + volume of cone
= 2/3 * πr³ + 1/3 * πr² h
= 2/3 * π * 3³ + 1/3 * π * 3² * 4
= 18π + 12 π
= 30 π cm³ = 94.2 cm³
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एक खिलौना एक अर्धगोले पर शंकु के आकार का है जिसकी त्रिज्या समान है, शंक्वाकार भाग के आधार का व्यास 6 सेमी है और इसकी ऊंचाई 4 सेमी है, खिलौने का सतह क्षेत्र है
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Slant height of the conical part is 5cm.
Now total surface area of toy equals to sum of Curved surface area of cone and curved surface
area of hemisphere. = 103.72cm^2(approx.)
Therefore the T.S.A. of the toy is 103.72cmsq
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