Question

a toy is in the shape of a cone mounted on a hemisphere of same base radius. If the volume of the toy is 231cm3 and diameter 7cm,find height of toy

Answer 1

Diameter= 7cm
radius = d/2 = 7/2 = 3.5cm
Volume of hemispherical part of the toy = 2/3πr³ = 2/3×22/7= 89.83cm³
Volume of conical part of the toy = 1/3πr²h
Volume of Toy = 231cm³
Volume of Cone + Volume of hemisphere = 231
1/3πr²h + 89.83 = 231
1/3×22/7×3.5×3.5×h = 231-89.83
h = 141.17× 3/22×0.5×3.5
Solve this u will get ur answer....

Answer 2

Answer:

Height of Toy is 11 cm

Step-by-step explanation:

We know that volume of cone

$= \frac{1}{3} \pi {r}^{2} h$

Volume of Hemisphere

$=\frac{2}{3} \pi {r}^{3}$

Volume of Toy=

$= > \: \frac{1}{3} \pi {r}^{2} h + \frac{2}{3} \pi {r}^{3} = 231$

Since Diameter = 7 cm

Radius=7/2

$\: \frac{1}{3} \pi {( \frac{7}{2} )}^{2} h + \frac{2}{3} \pi {( \frac{7}{2} })^{3} = 231 \\ \\ \frac{1}{3} \times \frac{22}{7} ( { \frac{7}{2} })^{2} (h + 2 \times \frac{7}{2} ) = 231 \\ \\ h + 7 = \frac{231 \times 3 \times 7 \times 2 \times 2}{22 \times 7 \times 7} \\ \\ h + 7 = \frac{33 \times 3 \times 2 \times 2}{22} \\ \\ h + 7 = 3 \times 3 \times 2 \\ \\ h + 7 = 18 \\ \\ h = 18 - 7 \\ \\ h = 11 \: cm$

Hope it helps you.