Question

A toy is in the shape of a night cincular cylinders
with a hemisphere
en the other the height and radius of the
part and 13cm and 5 on Prospectively
The gradie of the hemispherical and conical
port. Calculate the surface Darea cop the
the only drical
if height of the conical
part is 12 cm
as​

Answer 1

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• The Surface area of the toy = 770 cm²

Given:-

Radius of the hemisphere = Radius of the base of the cylinder = Radius of the base of the cone , r = 5 cm

Height of the hemisphere =  radius of hemisphere = 5 cm.

Height of the cylindrical part ,H = 13 cm

Total height of the toy = 30 cm

Solution:-

Let the height of the cone be h cm

Total height of the toy = height of the hemisphere +  height of the cylinder + height of the cone

30 = 5 +13 + h

30 = 18 + h

height of cone= 30-18

• height of cone, h = 12cm

Slant height of the cone (l) = √r² + h²

l = √ 5² +12²

l = √25 +144 = √169

l = 13 cm

Surface area of the toy = Curved surface area of the hemisphere +  curved surface area of the cylinder + curved surface area of the cone.

Surface area of the toy = 2πr² + 2πrh + πrl

= πr ( 2r + 2h + l)

= π× 5 (2×5 + 2× 13 + 13)

= π × 5 ( 10 +26 +13)

= π × 5 (49)

= 22/7 × 5 × 49

= (110 × 7)

= 770 cm²

Hence, the Surface area of the toy = 770 cm²

___________________________________________

Answer 2

Step-by-step explanation:

Given:-

Radius of the hemisphere = Radius of the base of the cylinder = Radius of the base of the cone , r = 5 cm

Height of the hemisphere = radius of hemisphere = 5 cm.

Height of the cylindrical part ,H = 13 cm

Total height of the toy = 30 cm

Solution:-

Let the height of the cone be h cm

Total height of the toy = height of the hemisphere + height of the cylinder + height of the cone

30 = 5 +13 + h

30 = 18 + h

height of cone= 30-18

height of cone, h = 12cm

Slant height of the cone (l) = √r² + h²

l = √ 5² +12²

l = √25 +144 = √169

l = 13 cm

Surface area of the toy = Curved surface area of the hemisphere + curved surface area of the cylinder + curved surface area of the cone.

Surface area of the toy = 2πr² + 2πrh + πrl

= πr ( 2r + 2h + l)

= π× 5 (2×5 + 2× 13 + 13)

= π × 5 ( 10 +26 +13)

= π × 5 (49)

= 22/7 × 5 × 49

= (110 × 7)

= 770 cm²

Hence, the Surface area of the toy = 770 cm²