Question

A toy is in the shape of hemisphere surmounted by a right circular cone. The height of the cone is 10 cm and the diameter of the base is 6 cm. Find the volume of the toy. If a cube circumstances the toy, then identify the difference between the volume of the cube and the toy. Also find the total surface area of the toy.

Just tell me the edge of cube.
$Who \: ever \: gives \: the \: correct \: answer \: with \: perfect \: explanation, \: I \: will \: be \: marking \: his/her \: answer \: as \: brainliest.$​

Answer 1

The answer to this question is as follows -

Radius of the hemisphere and the cone = 4 cm

Height of the cone = 4 cm

Volume of the toy = volume of the hemisphere + volume of the cone

A cube circumscribes the given solid. Therefore, edge of the cube should be 8 cm.

Volume of the cube = 83 = 512 cm3

Difference in the volumes of the cube and the toy = 512 - = 310.86 cm3

Total surface area of the toy = curved surface area of cone + curved surface area of hemisphere

= rl + 2r2, where l = == 4

= r (l + 2r)

= 4 (4 + 2 4)

=fraction numerator 88 cross times 4 left parenthesis square root of 2 plus 8 right parenthesis over denominator 7 end fraction

= 171.68 cm2

Please mark me as the brainliest

Answer 2

Answer:

answer is=171.68cm^2