A toy is made in the form of hemisphere surmounted by a right cone whose circular base is joined with the plane surface of the hemisphere. the radius of the base of the cone is 7cm and it's volume is 3/2 of the hemisphere calculate the height of the cone and the surface area of the toy correct to 2 places of the decimal [take π=3 1/2] plzz give me the solution....
Answers
Answered by
3
Thr radius of cone or hemisphere = 7 cm
suppose the height of cone = h cm
GIVEN :
volume of cone = 3/2 volume of hemisphere
=> 1/3 × 31/2 ×7×7 × h = 3/2 × 2/3 × 31/2 ×7×7×7
=> so ,..................................h = 21
now
=> slant height of cone = 22.135 cm
=> surface Area of toy = surface area of cone + surface area of hemisphere
=> 31/2 ×7 [ 22.135 + 14 ]
=> 2435.81 cm2
I hope it may helps u :-)
suppose the height of cone = h cm
GIVEN :
volume of cone = 3/2 volume of hemisphere
=> 1/3 × 31/2 ×7×7 × h = 3/2 × 2/3 × 31/2 ×7×7×7
=> so ,..................................h = 21
now
=> slant height of cone = 22.135 cm
=> surface Area of toy = surface area of cone + surface area of hemisphere
=> 31/2 ×7 [ 22.135 + 14 ]
=> 2435.81 cm2
I hope it may helps u :-)
Answered by
4
Continuation...
Surface area of the toy = 542.185+343 = 885.185 cm².
:)
Surface area of the toy = 542.185+343 = 885.185 cm².
:)
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