Question

A toy is made in the shape of a cylinder with one hemisphere struck to one end and a cone to the other end the length of the cylindrical part of the toy is 20 cm and it's Diameter is 10 cm if the slant height of the cone is 13 cm find the surface area of the toy​

Answer 1

Step-by-step explanation:

Given,length of cylindrical part=20cm Diameter=10cm

So, Radius=10/2cm = 5cm

Radius of hemispherical part=5cm

Radius of conical part=5cm

Slant height=13cm

So, Surface area of the toy

$= 2\pi {r}^{2} + 2\pi rh + \pi rl \: sq. \: unit$

$= \pi r(2r + 2h + l) \: sq. \: unit$

$= \frac{22}{7} \times 5(2 \times 5 + 2 \times 20 + 13) \: {cm}^{2}$

$= \frac{22}{7} \times 5 \times 63 \: {cm}^{2}$

$= 990 \: {cm}^{2}$

Hence, surface area of the toy is 990 cm^2.

Answer 2

Answer:

990cm^2

Step-by-step explanation:

length of cylindrical part =20cm

=diameter =10cm

=radius. =10/2cm=5cm

=Radius of hemispherical part =5cm

Radius of comical part =5cm

slant height =13cm

Surface area of the toy.

= 2πr^2+ 2πth + πru sq uints

= 22\7•5(2•5+2•20+13)cm,^2

=22\7•5•63cm^2

= 990cm ^2.

hence surface Area of the toy is 990cm^2.