Question

a toy train crosses 210 m and 122 m long tunnels in 25 and 17 seconds respectively. Find the length of train and speed of train.

Answer 1

In first case
Toy train cross the tunnel =210 m
Time taken =25 sec
Speed =distance /time
=210/25m/s
Same in 2nd case
Speed =distance /time
=122/17m/s
Now we remember here distance is combination of train length and tunnel length
So
(Train length +210)/25=speed
So( x+210)/25=(x+122)/17
17(x+210)=25(x+122)
17x+3570=25x+3050
8x=520
X=65
Length of train =65m
Now
Speed =(65+210)/25=275/25=11m/s
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Answer 2

In first case

Toy train cross the tunnel =210 m

Time taken =25 sec

Speed =distance /time

=210/25m/s

Same in 2nd case

Speed =distance /time

=122/17m/s

Now we remember here distance is combination of train length and tunnel length

So

(Train length +210)/25=speed

So( x+210)/25=(x+122)/17

17(x+210)=25(x+122)

17x+3570=25x+3050

8x=520

X=65

Length of train =65m

Now

Speed =(65+210)/25=275/25=11m/s

I think it is helpful for you If you like.