Question

A toy was sold at a gain 12%. Had it been sold for rs33 more, the gain would have been 14%. Find the cost price of the toy?

Answer 1

Answer:

if a toy was sold at 1 2% then the equation form is 112 upon 100 and then when you reduce it it becomes 28 X upon 25 and then when you it increased by 2% then it becomes 14% and the equation form is 114 X upon hundred and ten when you reduce that it becomes 57 X upon 50 and then takes the LCM of 50 and 25 that is 50 then 50 from the denominator and multiply it by 33 your answer is 1650

Answer 2

Answer:

let the cp be hundred rupees

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupees

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then,

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20 = ₹1650

let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20 = ₹1650hope it will help you mark as brainlist answer