a toy was sold at a gain of 12% if it has had been sold for 33 rupees more the gain would have been 14% find the cost price of the toy
Answers
Answer:₹1650
Step-by-step explanation:Let the cost price of the toy be ₹x.
Selling price of the toy when it was sold at 12%profit= {x X (100+12) ÷100}={ x X 112÷100}= ₹(112x÷100)
New selling price of the toy when it was sold at ₹33 more= ₹{(112x÷100)+33}
So, profit made by seller when he sold the toy at ₹{(112x÷100)+33}= S. P. - C. P.
= ₹(112x÷100 +33-x)
=₹{(112x+3300-100x) ÷ 100}
=₹{(12x+3300) ÷100}
But, according to question, he would made a profit of 14%.
So., ( profit X100) ÷C. P.=Profit %
or, {(12x+3300) ÷100 X 100} ÷x= 14
or, 12x+3300=14x
or, 14x -12x=3300
or, 2x=3300
or, x=1650.
Hence, the cost price of the toy is ₹1650.
Answer:
₹1650
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let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then,
let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20
let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20 = ₹1650
let the cp be hundred rupeesdifference between the two selling price is equal to rupees 114- rupee 112 equal to 2 rupeesif the difference of 2 cp= 100 if the difference of | CP = 100 /2 then, the different of 33 = 33×100/20 = ₹1650hope it will help you mark as brainlist answer