A track in the form of a ring whose inner circumference is 132meter and outter circumference is 176meter. Find the width of the track.
please find and give
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Step-by-step explanation:
Let inner radius=r1
and outer radius =r2
Inner circumference=132m
2×π×r1=132
2×22/7×r1=132
r1=132×7/44
r1=21m
Outer circumference=176m
2×π×r2=176
r2=176×7/44
r2=28m
width of track =r2-r1
=7m
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