a track is in the form of a ring whose inner and Outer circumference are 88 M and 132 M respectively find the width of the track
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hence the width of the track is7m
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Heya...
Here is your answer ----
Outer Circumference = 132 m
=> Radius = Circumference / 2π
=> Radius = 132 / (2 × 22/7)
=> Radius = 132 / (44/7)
=> Radius = 132 × 7/44
=> Radius = 3 × 7
=> Radius = 21 m
Inner Circumference = 88 m
=> Radius = Circumference / 2π
=> Radius = 88 / (2 × 22/7)
=> Radius = 88 / (44/7)
=> Radius = 88 × 7/44
=> Radius = 2 × 7
=> Radius = 14 m
Width of the ring = Outer Radius - Inner radius
= 21 - 14
= 7 m
HOPE IT HELPS.....!!!
Here is your answer ----
Outer Circumference = 132 m
=> Radius = Circumference / 2π
=> Radius = 132 / (2 × 22/7)
=> Radius = 132 / (44/7)
=> Radius = 132 × 7/44
=> Radius = 3 × 7
=> Radius = 21 m
Inner Circumference = 88 m
=> Radius = Circumference / 2π
=> Radius = 88 / (2 × 22/7)
=> Radius = 88 / (44/7)
=> Radius = 88 × 7/44
=> Radius = 2 × 7
=> Radius = 14 m
Width of the ring = Outer Radius - Inner radius
= 21 - 14
= 7 m
HOPE IT HELPS.....!!!
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