Question

A track is in the form of a ring whose inner and outer circumference are 88m and 132m , respectively . Find the width of the track and also the annulus.
I will mark you as a brainlest if a proper answer.
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Answer 1

Answer:

=7cm

Step-by-step explanation:

Outer Circumference = 132cm

⇒Radius = Circumference/2$\pi$

⇒Radius = 132/(2×22/7)

⇒Radius =132×7/44

⇒Radius =3×7

⇒Radius =21cm

Inner Circumference = 88cm

⇒Radius = Circumference/2$\pi$

⇒Radius =88/(2×22/7)

⇒Radius =88/(44/7)

⇒Radius =88×7/44

⇒Radius =2×7

⇒Radius =14cm

Width of the ring = Outer Radius - Inner Radius

⇒21-14

⇒$\huge\boxed{7cm}$